How do you evaluate #tan 45#?

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Answer 1 · 2016-05-29T08:08:05

Take a right triangle with equal side of length 1 hence by pythagorean theorem the hypotenuse is #sqrt2#.

Now #tan45=sin45/cos45=(1/sqrt2)/(1/sqrt2)=1#

In the right triangle above the angles are 90,45,45 because the triangle is isosceles.

Also in the triangle below we have that

sinA=(opposite side)/(Hypotenuse)

cosA=(adjacent side)/(Hypotenuse)

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