# How do you evaluate tan((5pi)/3)?

The intersection of the ray for $\frac{5 \pi}{3}$ with the unit circle is at the same place as the ray for $\left(- \frac{\pi}{3}\right)$
$\left(x , y\right) = \left(\frac{1}{2} , - \frac{\sqrt{3}}{2}\right)$
$\tan \left(\frac{5 \pi}{3}\right) = - \sqrt{3}$