How do you evaluate the definite integral #int (2/r^3)dr# from #[-3,-1]#?
1 Answer
Aug 10, 2017
The integral equals
Explanation:
Use the basic power rule.
#int_(-3)^(-1) 2/r^3 dr = [-r^-2]_(-3)^-1 = -(-1)^-2 - (-(-3)^-2) =-1 + 1/9 = -8/9#
Hopefully this helps!
