# How do you evaluate the expression (5/y)^x when x=2 and y=-1?

Oct 1, 2014

Substitute the value of x and y in the given expression;

${\left(\frac{5}{y}\right)}^{x}$

given x =2 and y =-1

${\left(\frac{5}{-} 1\right)}^{2}$

${\left(- 5\right)}^{2}$

( -5 x -5 )

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