Question

How do you evaluate the function `f(x)=6x^2+2x-12` for `f(x+1)`?

Answer 1

Function notation states that when given `f(a) = bx^2 + cx`, the answer is given by evaluating `ba^2 + ca`, since the `a` replaces the `x`.

Explanation:

Thus, we have:

`f(x + 1) = 6(x + 1)^2 + 2(x + 1) - 12`

`f(x + 1) = 6(x^2 + 2x + 1) + 2x + 2 - 12`

`f(x + 1)= 6x^2 + 12x + 6 + 2x + 2 - 12`

`f(x + 1) = 6x^2 + 14x - 4`

Hopefully this helps!