How do you evaluate the function #h(x)=4x-2# for h(x+2)?
1 Answer
Dec 30, 2015
You have to substitute x for x + 2
Explanation:
h(x) = 4x - 2
h(x + 2) = 4x - 2
h(x + 2) = 4(x + 2) - 2
h(x + 2) = 4x + 8 - 2
h(x + 2) = 4x + 6
h(x + 2) = 2(2x + 3)
