How do you evaluate the integral #int e^(5x)#?

1 Answer
Feb 23, 2017

Answer:

I got:
#e^(5x)/5+c#

Explanation:

Here you need to find a function (Primitive) that derived gives you #e^(5x)#.
We can guess immediately that this function could be:
#e^(5x)/5+"constant"#
that derived gives us the integrand;

or we can use the general rule to say that:
#inte^(kx)dx=e^(kx)/k+c#
where #k and c# are two constants.
We need the second constant #c# in the result to cover all the possibilities for our Primitive Function.