#lim_(xto0)(4-x^2)/(5-x^2)#?

2 Answers
Feb 8, 2018

#4/5#

Explanation:

This is easily solved by just plugging in #x=0#

#(4-(0)^2)/(5-(0)^2)=4/5#

#:.#

#lim_(x->0)(4-x^2)/(5-x^2)=4/5#

Feb 8, 2018

#4/5#

Explanation:

#"find the limit using "color(blue)"direct substitution"#

#rArrlim_(xto0)(4-x^2)/(5-x^2)=(4-0)/(5-0)=4/5#