Question

How do you evaluate the limit of `lim (sinx/x)` as `x->pi`?

Answer 1

`lim (sinx/x)=0` as `x->pi`

Explanation:

The difficulty lies in calculating `lim (sinx/x)` as `x->0`,

as when `x->0` both numerator and denominator tend to zero.

However, for `lim (sinx/x)` as `x->pi`, it is easier as

we have `sinpi/pi=0/pi=0`

Hence, `lim (sinx/x)=0` as `x->pi`.