Question

How do you evaluate the limit of `lim (x^2+3x-10)/(x^2+5x+6)` as `x->3`?

Answer 1

`lim_(x->3)(x^2 + 3x - 10)/(x^2 + 5x + 6)`

`=>lim_(x->3)((x + 5)(x -2 ))/((x + 5)(x + 6))`

`=>lim_(x->3) (x- 2)/(x + 6)`

`=> (3- 2)/(3 + 6)`

`=> 1/9`

Hopefully this helps!