Question

How do you evaluate the limit `(x^2-25)/(x+5)` as x approaches `-5`?

Answer 1

`lim_(x ->-5)(x^2 - 25)/(x + 5) = -10`

Explanation:

Start by eliminating through factorization:

`=lim_(x -> -5)(cancel((x + 5))(x - 5))/cancel(x + 5)`

`= -5 - 5`

`=-10`

Hopefully this helps!