How do you evaluate the power #-(1.2)^2#?
1 Answer
Oct 27, 2016
Explanation:
1.2 is being 'squared' Not the negative sign outside the bracket.
#rArr-(1.2)^2=-(1.2xx1.2)=-1.44#
1.2 is being 'squared' Not the negative sign outside the bracket.
#rArr-(1.2)^2=-(1.2xx1.2)=-1.44#