# How do you evaluate the power (2/3)^2?

Nov 4, 2016

$\frac{4}{9}$

#### Explanation:

${\left(\frac{2}{3}\right)}^{2} = \left(\frac{2}{3}\right) \times \left(\frac{2}{3}\right) = \frac{{2}^{2}}{{3}^{2}}$

$= \frac{2 \times 2}{3 \times 3}$

$= \frac{4}{9}$

Nov 4, 2016

${\left(\frac{2}{3}\right)}^{2}$ would be evaluated as $\frac{4}{9}$

#### Explanation:

In order to solve this problem, you first need to know that and number with an exponent of two means that the number with the exponent is multiplied by itself two times.
For example, if is was ${5}^{2}$, then we would expand it to be $5 \cdot 5$ to get an answer of $25$.

So for this espressions...
You would evaluate ${\left(\frac{2}{3}\right)}^{2}$ by expanding it to become $\frac{2}{3} \cdot \frac{2}{3}$ and multiplying out as normal to get $\frac{4}{9}$ as your answer.