How do you evaluate the six trigonometric functions given t=0? Trigonometry Right Triangles Trigonometric Functions of Any Angle 1 Answer MeneerNask Jul 15, 2017 We start with #sin0=0,cos0=1# which you should know. Explanation: #tan0=(sin0)/(cos0)=0/1=0# #cot0=1/(tan0)=1/0=+-oo# (undefined) #sec0=1/(cos0)=1/1=1# #csc0=1/(sin0)=1/0=+-oo# (undefined) Answer link Related questions How do you find the trigonometric functions of any angle? What is the reference angle? How do you use the ordered pairs on a unit circle to evaluate a trigonometric function of any angle? What is the reference angle for #140^\circ#? How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#? How do you use the reference angles to find #sin210cos330-tan 135#? How do you know if #sin 30 = sin 150#? How do you show that #(costheta)(sectheta) = 1# if #theta=pi/4#? See all questions in Trigonometric Functions of Any Angle Impact of this question 4383 views around the world You can reuse this answer Creative Commons License