How do you evaluate the six trigonometric functions given t=−0.56?

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Answer 1 · 2018-02-20T11:39:33

As calculated below

Given #t = -0.56^c#

#sin t = sin (-0.56) = - 0.5312#

#cos t = cos (-0.56) = 0.8473#

#tan t = tan (-0.56) = - 0.6269#

#csc t = 1 / sin (-0.56) = -1/0.5312 = -1.8825#

#sec t = 1/cos (-.56) = 1/0.8473 = 1.1802#

#cot t = 1 / tan t = 1 / -0.6269 = -1.5952#