# How do you evaluate (u^2- v^2)/(uv) for u = 4 and v = 2?

$1 \frac{1}{2}$
In $\frac{{u}^{2} - {v}^{2}}{u v}$, if $u = 4$ and $v = 2$
$\frac{{u}^{2} - {v}^{2}}{u v} = \frac{{4}^{2} - {2}^{2}}{4 \times 2} = \frac{16 - 4}{4 \times 2} = \frac{3 \cancel{12}}{1 \cancel{4} \times 2} = \frac{3}{2} = 1 \frac{1}{2}$