Question

How do you evaluate `x-(absz+x)` when x=6, z=3?

Answer 1

`-3`

Explanation:

First step is to evaluate the contents of the bracket and subtract the result from x.

The `color(blue)"absolute value"` is always positive since it is a measure of the distance of a value from zero.

`"That is " |-4|=|4|=4` since both - 4 and 4 are 4 units from zero.

Substitute given values into the expression.

`rArr(|3|+6)=(3+6)=9larr" evaluation of bracket"`

`rArr6-9=-3larr" evaluation of expression"`