How do you evaluate #x-(absz+x)# when x=6, z=3?

1 Answer
Jim G.
Dec 21, 2016

#-3#

Explanation:

First step is to evaluate the contents of the bracket and subtract the result from x.

The #color(blue)"absolute value"# is always positive since it is a measure of the distance of a value from zero.

#"That is " |-4|=|4|=4# since both - 4 and 4 are 4 units from zero.

Substitute given values into the expression.

#rArr(|3|+6)=(3+6)=9larr" evaluation of bracket"#

#rArr6-9=-3larr" evaluation of expression"#

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