How do you expand and simplify #2(3x+4)-3(4x-5)#?

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Answer 1 · 2016-12-13T04:27:36

#-6x + 23#

Step 1) Distribute the constant outside each parenthesis across each term within their respective parenthesis:

#((2*3x) + (2*4)) - ((3*4x) - (3*5))#

#(6x + 8) - (12x - 15)#

Step 2) Remove the parenthesis, be careful to manage the signs correctly and then group like terms:

#6x + 8 - 12x color(red)(+) 15#

#6x - 12x + 8 + 15#

Step 3) Combine like terms:

#(6 - 12)x + 23#

#-6x + 23#