How do you expand $ln(x/sqrt(x^6+3))$ ?

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Answer 1 · 2016-09-04T22:25:22

The expression can be simplified to $lnx - 1/2ln(x^6 + 3)$

Start by applying the rule $log_a(n/m) = log_a(n) - log_a(m)$ .

$=>ln(x) - ln(sqrt(x^6 + 3))$

Write the $√$ in exponential form.

$=> lnx - ln(x^6 + 3)^(1/2)$

Now, use the rule $log(a^n) = nloga$ .

$=>lnx - 1/2ln(x^6 + 3)$

This is as far as we can go.

Hopefully this helps!

How do you expand ln(x/sqrt(x^6+3))ln(x/sqrt(x^6+3))?