How do you expand $log (\frac{1}{A} B C)$ $log (1/ABC)$ ?

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Answer 1 · 2015-10-25T13:17:48

$log (\frac{1}{A} B C) = - log (A) + log (B) + log (C)$ $log(1/ABC)=-log(A)+log(B)+log(C)$

$[1] log (\frac{1}{A} B C)$ $[1]" "log(1/ABC)$

Property: ${log}_{b} (m n) = {log}_{b} (m) + {log}_{b} (n)$ $log_b(mn)=log_b(m)+log_b(n)$

$[2] = log (\frac{1}{A}) + log (B) + log (C)$ $[2]" "=log(1/A)+log(B)+log(C)$

Property: ${log}_{b} (\frac{m}{n}) = {log}_{b} (m) - {log}_{b} (n)$ $log_b(m/n)=log_b(m)-log_b(n)$

$[3] = log (1) - log (A) + log (B) + log (C)$ $[3]" "=log(1)-log(A)+log(B)+log(C)$

Property: ${log}_{b} (1) = 0$ $log_b(1)=0$

$[4] = - log (A) + log (B) + log (C)$ $[4]" "=color(blue)(-log(A)+log(B)+log(C))$

How do you expand log(1ABC)log (1/ABC) ?