Question

How do you expand `log (6/5)^6`?

Answer 1

`log(6/5)^6=6log6-6log5`

Explanation:

As `log(a/b)=loga-logb` and `loga^m=mloga`

hence `log(6/5)^6`

= `6log(6/5)`

= `6(log6-log5)`

= `6log6-6log5`