# How do you expand log_6(6x)?

I found: $1 + {\log}_{6} \left(x\right)$
${\log}_{6} \left(6 x\right) = {\log}_{6} \left(6\right) + {\log}_{6} \left(x\right) = 1 + {\log}_{6} \left(x\right)$