How do you expand Log_b( sqrt57/74)? Precalculus Properties of Logarithmic Functions Functions with Base b 1 Answer A. S. Adikesavan May 20, 2016 ((1/2) log 57 - log 74)/log b=((1/2) ln 57 - ln 74)/ln b Explanation: Use log_b a=log_c a/log_c b and log_b a^n=n log_b a. Here, the given logarithm = log_b( sqrt57 /74) =log( sqrt57 /74)/log b=ln( sqrt57 /74)/ln b =( log 57/2 - log 74)/log b=( ln 57/2 - ln 74)/ln b Answer link Related questions What is the exponential form of log_b 35=3? What is the product rule of logarithms? What is the quotient rule of logarithms? What is the exponent rule of logarithms? What is log_b 1? What are some identity rules for logarithms? What is log_b b^x? What is the reciprocal of log_b a? What does a logarithmic function look like? How do I graph logarithmic functions on a TI-84? See all questions in Functions with Base b Impact of this question 1621 views around the world You can reuse this answer Creative Commons License