How do you express #1/(5sqrt(x^2))# as a fractional exponent?

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Answer 1 · 2017-09-06T14:13:09

#1/5 * x^(2 * -1/2) = 1/5 * x^-1#

...best I can do.

Answer 2 · 2017-09-06T14:28:21

Please see processes below.....

I don't really know if you actually mean.... #1/root(5)x^2 or 1/(5 sqrtx^2)#

But which so ever way...

Here is the processes below;

Process 1

For, #-> 1/root(5)x^2#

#1/root(5)x^2#

Note that #-> root(5)a = a^(1/5)#

#rArr 1/x^(2 xx 1/5)#

#rArr 1/x^(2/5) -> Answer#, Since it's a fractional exponent, hence the answer should have been #x^(-2/5)#, since #1/a = a^-1#

Process 2

For, #-> 1/(5 sqrtx^2)#

#1/(5 sqrtx^2)#

#rArr 1/(5 xx sqrtx^2)#

Note that #-> sqrtx^2 = x#

#rArr 1/(5 xx x)#

#rArr 1/(5x) -> Answer#

Which ever way your questions is asked, those above processes gives you the solution to either..

Hope it's crystal??