How do you express #( 2x)/(1-x^3)# in partial fractions?
On simplifying the Right Hand Side and comparing the coefficients
on both sides it would be
A-B=0, A+C=0 and A+B-C=2
Add the first two equation to get B-C= 2A.
Plug in this value in the next equation to get 3A=2, that is
The required partial fractions would be