How do you express a single logarithm for #log_e M + log_e T#?

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Answer 1 · 2015-05-20T06:05:17

There is a rule for logarithms where you can combine a sum of them into one logarithm that multiplies the respective arguments. So:

#log_e(M)+log_e(T) = lnM+lnT = ln(MT)#

Similarly, #log_e(M)-log_e(T) = lnM-lnT = ln(M/T)#

How do you express a single logarithm for #log_e *M + log_e *T#?