How do you express #f(theta)=sin(theta/4)+tan(theta/2)+cot(theta/4)# in terms of trigonometric functions of a whole theta?

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Feb 17, 2017

Answer:

#=sqrt(1/2(1-costheta))+2csctheta#

Explanation:

#f=sin(theta/2)+tan(theta/2)+1/tan(theta/2)#

#=sqrt(1/2(1-costheta))+2(1+tan^2(theta/2))/(2tan(theta/2))#

#=sqrt(1/2(1-costheta))+2/sintheta#

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