Question

How do you express `sin^2 theta - sec theta + csc theta` in terms of `cos theta`?

Answer 1

`sin^2theta-sectheta+csctheta=1-cos^2theta-1/costheta+1/sqrt(1-cos^2theta)`

Explanation:

`sin^2theta-sectheta+csctheta`

= `1-cos^2theta-1/costheta+1/sintheta`

= `1-cos^2theta-1/costheta+1/sqrt(sin^2theta)`

= `1-cos^2theta-1/costheta+1/sqrt(1-cos^2theta)`