# How do you express the following using fractional exponents: (3sqrtx)/(3sqrtr)?

I think the intended expression in the question was $\frac{\sqrt[3]{x}}{\sqrt[3]{r}}$
If I am correct, then you could express this as ${x}^{\frac{1}{3}} {r}^{- \frac{1}{3}}$
Notice that ${\left({x}^{\frac{1}{3}}\right)}^{3} = {x}^{\frac{1}{3} \cdot 3} = {x}^{1} = x$
So ${x}^{\frac{1}{3}}$ is indeed the cube root of $x$, $\sqrt[3]{x}$
Note also that ${\left({r}^{- \frac{1}{3}}\right)}^{3} = {r}^{- \frac{1}{3} \cdot 3} = {r}^{- 1} = \frac{1}{r}$