# How do you express (x^3+1) / (x^2+4) in partial fractions?

$\frac{{x}^{3} + 1}{{x}^{2} + 4} = x - \frac{4 x - 1}{{x}^{2} + 4}$
$\frac{{x}^{3} + 1}{{x}^{2} + 4} = \frac{x \left({x}^{2} + 4\right)}{{x}^{2} + 4} + \frac{- 4 x + 1}{{x}^{2} + 4}$
= $x - \frac{4 x - 1}{{x}^{2} + 4}$