How do you factor #1-2 sin^2 x + sin^4 x#?
1 Answer
Mar 14, 2018
Explanation:
#"factor using the a-c method "#
#"let "u=sin^2x#
#"the factors of + 1 which sum to - 2 are - 1 and - 1"#
#rArr1-2u+u^2=(1-u)(1-u)=(1-u)^2#
#"change u back to "sin^2x#
#rArr1-2sin^2x+sin^4x#
#=(1-sin^2x)(1-sin^2x)#
#=(1-sin^2x)^2#
