Question

How do you factor 10t² + t - 2?

Answer 1

Given the expression `10t^2 + t -2`
we could set the given expression equal to zero
and use the quadratic roots formula

`t= (-b+-sqrt(b^2-4ac))/(2a)`

which evaluates as `t= -1/2` or `t= 2/5`

So `(t+1/2)` and `(t-2/5)` are both factors of the given expression

with the remaining factor `=10`

`10t^2 + t -2 = 10(t+1/2)(t-2/5)`