How do you factor #10x^2-20xy+10y^2#?

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Answer 1 · 2017-02-03T11:12:30

The answer is #=10(x-y)^2#

We need

#(a-b)^2=a^2-2ab+b^2#

So,

#10x^2-20xy+10y^2#

#=10(x^2-2xy+y^2)#

#=10(x-y)(x-y)#

#=10(x-y)^2#