How do you factor #12x^2 + 100x - 72#?

1 Answer
May 28, 2016

4(3x - 2)(x + 9)

Explanation:

#f(x) = 4y = 4(3x^2 + 25x - 18)#
Factor y by the new AC Method (Socratic Search).
#y = (3x^2 + 25x - 18) =# 3(x + p)(x + q)
Converted trinomial: #y' = x^2 + 25x - 54 =# (x + p')(x + q')
p' and q' have opposite signs because ac < 0.
Factor pairs of (ac = -54) -->...(-2, 27). This sum is 25 = b. Then, p' = -2 and q' = 27.
Back to original trinomial y --> #p = (p')/a = -2/3#, and
#q = (q')/a = 27/3 = 9#.
Factored form: #y = 3(x - 2/3)(x + 9) = (3x - 2)(x + 9).#
Therefor,

f(x) = 4y = 4(3x - 2)(x + 9)