How do you factor #12x^2-39x+9#?

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Answer 1 · 2017-08-07T03:17:16

We can play with factors of 12 (1x12, 2x6, 3,4) and factors of 9 (1x9, 3x3) to combine and factor the expression as:

#(12x - 3)(x - 3)#

Answer 2 · 2017-08-07T08:14:29

#3(4x-1)(x-3)#

#12x^2 -39x+9#

Take out a common factor of #3# first

#3(4x^2-13x+3)#

Find factors of #4 and 3# whose products ADD to 13.

#(4xx3)+(1xx1) =13#

#3(4x-1)(x-3)#