How do you factor #16z^2 - 24z + 9#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer iceman Sep 26, 2015 #16z^2−24z+9=(4z-3)^2# Explanation: #16z^2−24z+9=># use: #a^2-2ab+b^2=(a-b)^2:#where#:a=4z,b=3:# #=(4z-3)^2# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 1958 views around the world You can reuse this answer Creative Commons License