How do you factor #2a^2+22a+60#?

2 Answers
Sidharth
Mar 27, 2015

#2( a ^{ 2 }+11a\quad +30 \) #

Product = 30

Sum = 11

Factors = 5,6

#2( a ^{ 2 }+11a\quad +30 ) \\ \\ =2[\quad { a }^{ 2 }\quad \quad +\quad 5a\quad +6a\quad +\quad 30]\\ =2[a(a+6)\quad +\quad 6(a+5)]\\ =2(a+6)(a+5)#

Hence factored

Sidharth
Mar 27, 2015

#2( a ^{ 2 }+11a\quad +30 \) #

Product = 30

Sum = 11

Factors = 5,6

#2( a ^{ 2 }+11a\quad +30 ) \\ \\ =2[\quad { a }^{ 2 }\quad \quad +\quad 5a\quad +6a\quad +\quad 30]\\ =2[a(a+6)\quad +\quad 6(a+5)]\\ =2(a+6)(a+5)#

Hence factored

Related questions
See all questions in Factorization of Quadratic Expressions
Impact of this question
2141 views around the world
You can reuse this answer
Creative Commons License