How do you factor 2a^2+3a+1?

1 Answer
May 3, 2016

2a^2+3a+1=2(a+1/2)(a+1)

Explanation:

We evaluate the discriminant: Delta=B^2-4AC=9-8=1.
The roots are given by a=(-B pm sqrt(Delta))/(2A).
Here we have a_1=(-3+1)/4=-1/2 and a_2=(-3-1)/4=-1.
The factored form is A(a-a_1)(a-a_2)=2(a+1/2)(a+1).