# How do you factor 2p^2+2p-4?

May 22, 2015

Find it roots. I'll use Bhaskara. But, first, let's just factor out one thing from your original function: $2 \left({p}^{2} + p - 2\right)$. Now, let's find the roots for the original:

$\frac{- 2 \pm \sqrt{4 - 4 \left(2\right) \left(- 4\right)}}{4}$
$\frac{- 2 \pm 6}{4}$

Your roots are $p = - 2$ and $p = 1$, which can be rewritten as $p + 2 = 0$ and $p - 1 = 0$.

Thus,

$2 \left({p}^{2} + p - 2\right) = 2 \left(p + 2\right) \left(p - 1\right)$