How do you factor #2p^2+2p-4#?

1 Answer
Guilherme N.
May 22, 2015

Find it roots. I'll use Bhaskara. But, first, let's just factor out one thing from your original function: #2(p^2+p-2)#. Now, let's find the roots for the original:

#(-2+-sqrt(4-4(2)(-4)))/4#
#(-2+-6)/4#

Your roots are #p=-2# and #p=1#, which can be rewritten as #p+2=0# and #p-1=0#.

Thus,

#2(p^2+p-2)=2(p+2)(p-1)#

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