How do you factor 2p^2+2p-4?

1 Answer
May 22, 2015

Find it roots. I'll use Bhaskara. But, first, let's just factor out one thing from your original function: 2(p^2+p-2). Now, let's find the roots for the original:

(-2+-sqrt(4-4(2)(-4)))/4
(-2+-6)/4

Your roots are p=-2 and p=1, which can be rewritten as p+2=0 and p-1=0.

Thus,

2(p^2+p-2)=2(p+2)(p-1)