How do you factor #2x^2 + 17x - 9#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer vmoukas Apr 11, 2018 #[x- ((-17 + sqrt106)/4]*[x-((-17 - sqrt106)/4]# Explanation: with the discriminant #D = 17^2 - 4*2(-9)= 34+72 = 106# #x1,2= (-17 +- sqrt106)/4 # Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 2199 views around the world You can reuse this answer Creative Commons License