How do you factor #2x^2+22x+56#?
1 Answer
May 14, 2017
Explanation:
#"take out a "color(blue)"common factor"" of 2"#
#rArr2(x^2+11x+28)#
#"to factor the quadratic 'split' the x term"#
#"that is " x^2+4x+7x+28#
#"factorising each 'pair' gives"#
#color(red)(x)(x+4)color(red)(+7)(x+4)#
#"take out the common factor " (x+4)#
#(x+4)(color(red)(x+7))#
#rArr2x^2+22x+56=2(x+4)(x+7)#
