How do you factor #2x^2 = 9x -4#?

Question

564 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-31T17:27:24

Please see below for factors. As it is an equation, it can be solved for #x# too and #x=4# or #x=1/2#.

#2x^2=9x-4#

#hArr2x^2-9x+4=0#

or #2x^2-8x-x+4=0#

or #2x(x-4)-1(x-4)=0#

or #(2x-1)(x-4)=0#

Here factorization is complete, but as it is an equation, we can solve it for #x# as well.

#(2x-1)(x-4)=0# means either

#2x-1=0# i.e #x=1/2# or

#x-4=0#/I.e. #x=4#