How do you factor #2x^2+9x+7#?

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Answer 1 · 2017-05-17T16:40:12

#(2x+7)(x+1)#

#2x^2 +9x+7#

We need to find factors of #2 and 7# whose products add to #9#.

As they are both prime numbers, there are only 2 options for the sum of their products.. either #9 or 15#

We can realise that #(2xx1) + (7xx1)# will give #2+7=9#

#(2x+7)(x+1)#

Check by multiplying out. (FOIL)

#= 2x^2+2x+7x+7#

#=2x^2 +9x+7#