How do you factor #2x^2 + x - 6#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer George C. Jun 13, 2015 #2x^2+x-6 = (2x-3)(x+2)# Explanation: Let #f(x) = 2x^2+x-6#. Notice that #f(-2) = 8-2-6 = 0#, so #(x+2)# is a factor. The other factor must be #(2x-3)# to get the coefficient of #x^2# and the constant term when we multiply them... #2x^2+x-6 = (2x-3)(x+2)# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 17290 views around the world You can reuse this answer Creative Commons License