# How do you factor 2x^3+16 ?

Aug 25, 2016

$2 \left({x}^{3} + 8\right) = 2 \left(x + 2\right) \left({x}^{2} - 2 x + 4\right)$

#### Explanation:

Always look for a common factor first.

Both terms can be divided by 2.

$2 \left({x}^{3} + 8\right)$

Both ${x}^{3} \mathmr{and} 8$ are cube numbers. The sum or difference of cubes can be factored according to:

$\left({a}^{3} + {b}^{3}\right) = \left(a + b\right) \left({a}^{2} - a b + {b}^{2}\right)$
$\left({a}^{3} - {b}^{3}\right) = \left(a + b\right) \left({a}^{2} + a b + {b}^{2}\right)$

$2 \left({x}^{3} + 8\right) = 2 \left(x + 2\right) \left({x}^{2} - 2 x + 4\right)$