How do you factor #2x^4+5x^2+3#?

1 Answer
May 11, 2017

#2x^4+5x^2+3=(x^2+1)(2x^2+3)#

Explanation:

Don't get scared by the fact that there is a fourth power of #x#. The only thing to notice here is that only powers of #x^2# are present in the expression. Let's use that to our advantage.

Assume #x^2=a#. Substituting this into our expression, we get
#2x^4+5x^2+3=2a^2+5a+3#.

The problem is now basically that of middle term factorization. We notice that #2a^2+5a+3=2a^2+2a+3a+3=2a(a+1)+3(a+1)=(a+1)(2a+3)#.

But we're not done yet! We must put back the substituted value of #a#, i.e. #x^2#. Doing so, we get:

#2x^4+5x^2+3=(x^2+1)(2x^2+3)#