How do you factor #3(2x-1)^2 (2) (x+3)^(1/2) + (2x-1)^3 (1/2) (x+3)^(-1/2)#? Algebra Polynomials and Factoring Factorization of Quadratic Expressions 1 Answer bp Oct 9, 2015 #(7(2x-1)^2 (2x+5))/(2(x+3)^(1/2))# Explanation: Take out common factor #(2x-1)^2# and simplify, #(2x-1)^2 {6(x+3)^(1/2) + (2x-1)/(2(x+3)^(1/2)}}# #(2x-1)^2{(12x+36 +2x-1)/(2(x+3)^(1/2)}}# #((2x-1)^2 (14x+35))/(2(x+3)^(1/2))# #(7(2x-1)^2 (2x+5))/(2(x+3)^(1/2))# Answer link Related questions How do you factor trinomials? What is factorization of quadratic expressions? How do you factor quadratic equations with a coefficient? What are some examples of factoring quadratic expressions? How do you check that you factored a quadratic correctly? How do you factor #x^2+16x+48#? How do you factor #x^2-9x+20#? Question #3fdac How do you factor #8+z^6#? There is no GCF to be factor out, so is there another method to complete this? How do you factor #2t^2+7t+3#? See all questions in Factorization of Quadratic Expressions Impact of this question 4255 views around the world You can reuse this answer Creative Commons License