How do you factor #-36n^2+48n-15#?

1 Answer
Sep 1, 2016

#-36n^2+48n-15=color(green)(-3(6n-5)(2n-1))#

Explanation:

#-36n^2+48n-15#
#color(white)("XXX")=-(6n)^2+8(6n)-15#

(replacing #6n# with #p# temporarily)
#color(white)("XXX")=-p^2+8p-15#

#color(white)("XXX")=(-1)(p-5)(p-3)#

(restoring #6n# back in place of #p#)
#color(white)("XXX")=(-1)(6n-5)(6n-3)#

#color(white)("XXX")=(-3)(6n-5)(2n-1)#