Question

How do you factor `3x^2+6x-9`?

Answer 1

Refer to explanation

Explanation:

We have that

`3x^2+6x-9=3*(x^2+2x+1)-9-3=3*(x+1)^2-12=(sqrt3*(x+1))^2-(sqrt12)^2=(sqrt3*(x+1)+2sqrt3)*(sqrt3*(x+1)-2sqrt3)=sqrt3*(x+3)*sqrt3(x-1)=3(x+3)(x-1)`

Finally

`3x^2+6x-9=3(x+3)(x-1)`