How do you factor #40-22x+x^2#?

1 Answer
Apr 17, 2017

#(x-20)(x-2)#

Explanation:

It does not matter whether the #x^2# term is at the beginning or end, as long as the #x# term is in the middle.

You might find it easier if the expression is changed to
#x^2color(red)( -)22xcolor(blue)(+)40" "larr# note the colours

Find two factors of #40# which #color(blue)("ADD")# to #22" "# ( the x term)
These are #20xx2 = 40 and 20+2 = 22#

The signs in the brackets will be #color(blue)("THE SAME")#

They will both be #color(red)("NEGATIVE")#

#(x-20)(x-2)#

Multiply out to check:

#x^2 color(red)(-2x -20x) color(blue)(+) 40#

#=x^2color(red)( -22)xcolor(blue)(+)40#